Base | Representation |
---|---|
bin | 110011100001000111000… |
… | …000100000000011100111 |
3 | 110112102222201100120200210 |
4 | 303201013000200003213 |
5 | 431000410024144133 |
6 | 11310211003110503 |
7 | 513526361411304 |
oct | 63410700400347 |
9 | 13472881316623 |
10 | 3540244365543 |
11 | 1145455717706 |
12 | 492158812433 |
13 | 1c8ac754c112 |
14 | c34c4d380ab |
15 | 6215352d763 |
hex | 338470200e7 |
3540244365543 has 16 divisors (see below), whose sum is σ = 4781211655680. Its totient is φ = 2329734179136.
The previous prime is 3540244365529. The next prime is 3540244365547. The reversal of 3540244365543 is 3455634420453.
3540244365543 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3540244365543 - 216 = 3540244300007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3540244365492 and 3540244365501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3540244365547) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 771705 + ... + 2770562.
It is an arithmetic number, because the mean of its divisors is an integer number (298825728480).
Almost surely, 23540244365543 is an apocalyptic number.
3540244365543 is a deficient number, since it is larger than the sum of its proper divisors (1240967290137).
3540244365543 is a wasteful number, since it uses less digits than its factorization.
3540244365543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3546566.
The product of its (nonzero) digits is 10368000, while the sum is 48.
Adding to 3540244365543 its reverse (3455634420453), we get a palindrome (6995878785996).
The spelling of 3540244365543 in words is "three trillion, five hundred forty billion, two hundred forty-four million, three hundred sixty-five thousand, five hundred forty-three".
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