3540497011 has 8 divisors (see below), whose sum is σ = 3657544704. Its totient is φ = 3423626760.

The previous prime is 3540496963. The next prime is 3540497041. The reversal of 3540497011 is 1107940453.

3540497011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3540497011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3540497041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3175 + ... + 84208.

It is an arithmetic number, because the mean of its divisors is an integer number (457193088).

Almost surely, 2^3540497011 is an apocalyptic number.

3540497011 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

3540497011 is a deficient number, since it is larger than the sum of its proper divisors (117047693).

3540497011 is a wasteful number, since it uses less digits than its factorization.

3540497011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88721.

The product of its (nonzero) digits is 15120, while the sum is 34.

The square root of 3540497011 is about 59502.0756864834. The cubic root of 3540497011 is about 1524.1278913611.

The spelling of 3540497011 in words is "three billion, five hundred forty million, four hundred ninety-seven thousand, eleven".