Base | Representation |
---|---|
bin | 1010010011011110010… |
… | …11001100010001111011 |
3 | 1020211212112021201000021 |
4 | 11021233023030101323 |
5 | 21300044421220011 |
6 | 430352142151311 |
7 | 34402515535336 |
oct | 5115713142173 |
9 | 1224775251007 |
10 | 354052523131 |
11 | 127175467a1a |
12 | 5874b582537 |
13 | 2750534c9c8 |
14 | 131c9b7961d |
15 | 9322c01471 |
hex | 526f2cc47b |
354052523131 has 4 divisors (see below), whose sum is σ = 354613621264. Its totient is φ = 353491425000.
The previous prime is 354052523089. The next prime is 354052523159. The reversal of 354052523131 is 131325250453.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131325250453 = 19 ⋅6911855287.
It is a cyclic number.
It is not a de Polignac number, because 354052523131 - 211 = 354052521083 is a prime.
It is a super-2 number, since 2×3540525231312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (354052526131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280548120 + ... + 280549381.
It is an arithmetic number, because the mean of its divisors is an integer number (88653405316).
Almost surely, 2354052523131 is an apocalyptic number.
354052523131 is a deficient number, since it is larger than the sum of its proper divisors (561098133).
354052523131 is an equidigital number, since it uses as much as digits as its factorization.
354052523131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 561098132.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 354052523131 its reverse (131325250453), we get a palindrome (485377773584).
The spelling of 354052523131 in words is "three hundred fifty-four billion, fifty-two million, five hundred twenty-three thousand, one hundred thirty-one".
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