354053113 has 4 divisors (see below), whose sum is σ = 354842100. Its totient is φ = 353264128.

The previous prime is 354053107. The next prime is 354053123. The reversal of 354053113 is 311350453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 200590569 + 153462544 = 14163^2 + 12388^2 .

It is a cyclic number.

It is not a de Polignac number, because 354053113 - 2¹³ = 354044921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (354053123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393820 + ... + 394717.

It is an arithmetic number, because the mean of its divisors is an integer number (88710525).

Almost surely, 2^354053113 is an apocalyptic number.

It is an amenable number.

354053113 is a deficient number, since it is larger than the sum of its proper divisors (788987).

354053113 is an equidigital number, since it uses as much as digits as its factorization.

354053113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 788986.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 354053113 is about 18816.2991313382. The cubic root of 354053113 is about 707.4397726204.

The spelling of 354053113 in words is "three hundred fifty-four million, fifty-three thousand, one hundred thirteen".