Base | Representation |
---|---|
bin | 1010010011101001011… |
… | …01110111110000110101 |
3 | 1020212010000020102120220 |
4 | 11021310231313300311 |
5 | 21300242222001323 |
6 | 430405303044553 |
7 | 34405025040501 |
oct | 5116455676065 |
9 | 1225100212526 |
10 | 354145500213 |
11 | 1272129a1a8a |
12 | 58776740759 |
13 | 2751b6a4a2b |
14 | 131d825d301 |
15 | 932ae6a0e3 |
hex | 5274b77c35 |
354145500213 has 4 divisors (see below), whose sum is σ = 472194000288. Its totient is φ = 236097000140.
The previous prime is 354145500101. The next prime is 354145500217. The reversal of 354145500213 is 312005541453.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 354145500213 - 213 = 354145492021 is a prime.
It is a super-2 number, since 2×3541455002132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (354145500217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59024250033 + ... + 59024250038.
It is an arithmetic number, because the mean of its divisors is an integer number (118048500072).
Almost surely, 2354145500213 is an apocalyptic number.
It is an amenable number.
354145500213 is a deficient number, since it is larger than the sum of its proper divisors (118048500075).
354145500213 is a wasteful number, since it uses less digits than its factorization.
354145500213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118048500074.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 354145500213 in words is "three hundred fifty-four billion, one hundred forty-five million, five hundred thousand, two hundred thirteen".
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