Base | Representation |
---|---|
bin | 10000000110111001110001… |
… | …10110010000100110110111 |
3 | 11122102021012122200210210220 |
4 | 20003130320312100212313 |
5 | 14120321313023204012 |
6 | 203200233542345423 |
7 | 10314060002014146 |
oct | 1003347066204667 |
9 | 148367178623726 |
10 | 35421549038007 |
11 | 10317215aa3130 |
12 | 3b80b2512b273 |
13 | 169c31241acc2 |
14 | 8a65aac0775d |
15 | 4165e0b4408c |
hex | 203738d909b7 |
35421549038007 has 16 divisors (see below), whose sum is σ = 51557712440448. Its totient is φ = 21452830771680.
The previous prime is 35421549037997. The next prime is 35421549038009. The reversal of 35421549038007 is 70083094512453.
It is not a de Polignac number, because 35421549038007 - 231 = 35419401554359 is a prime.
It is a super-3 number, since 3×354215490380073 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35421549038009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 369318973 + ... + 369414870.
It is an arithmetic number, because the mean of its divisors is an integer number (3222357027528).
Almost surely, 235421549038007 is an apocalyptic number.
35421549038007 is a deficient number, since it is larger than the sum of its proper divisors (16136163402441).
35421549038007 is a wasteful number, since it uses less digits than its factorization.
35421549038007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738735310.
The product of its (nonzero) digits is 3628800, while the sum is 51.
The spelling of 35421549038007 in words is "thirty-five trillion, four hundred twenty-one billion, five hundred forty-nine million, thirty-eight thousand, seven".
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