Base | Representation |
---|---|
bin | 10000000111000011111011… |
… | …10101110011010110111101 |
3 | 11122102210021122111020221011 |
4 | 20003201331311303112331 |
5 | 14120413444341412110 |
6 | 203202535000035221 |
7 | 10314342060210655 |
oct | 1003417565632675 |
9 | 148383248436834 |
10 | 35427001513405 |
11 | 10319563857647 |
12 | 3b81ba7162b11 |
13 | 169c9a0c321c8 |
14 | 8a696700d365 |
15 | 41680e67748a |
hex | 20387dd735bd |
35427001513405 has 16 divisors (see below), whose sum is σ = 43026067929600. Its totient is φ = 27999180445248.
The previous prime is 35427001513373. The next prime is 35427001513411. The reversal of 35427001513405 is 50431510072453.
It is a cyclic number.
It is not a de Polignac number, because 35427001513405 - 25 = 35427001513373 is a prime.
It is a super-3 number, since 3×354270015134053 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10841539 + ... + 13725631.
It is an arithmetic number, because the mean of its divisors is an integer number (2689129245600).
Almost surely, 235427001513405 is an apocalyptic number.
It is an amenable number.
35427001513405 is a deficient number, since it is larger than the sum of its proper divisors (7599066416195).
35427001513405 is a wasteful number, since it uses less digits than its factorization.
35427001513405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2913780.
The product of its (nonzero) digits is 252000, while the sum is 40.
Adding to 35427001513405 its reverse (50431510072453), we get a palindrome (85858511585858).
The spelling of 35427001513405 in words is "thirty-five trillion, four hundred twenty-seven billion, one million, five hundred thirteen thousand, four hundred five".
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