3547479343 has 4 divisors (see below), whose sum is σ = 3548726488. Its totient is φ = 3546232200.

The previous prime is 3547479307. The next prime is 3547479347. The reversal of 3547479343 is 3439747453.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3439747453 = 79 ⋅43541107.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3547479343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3547479347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 619296 + ... + 624997.

It is an arithmetic number, because the mean of its divisors is an integer number (887181622).

Almost surely, 2^3547479343 is an apocalyptic number.

3547479343 is a deficient number, since it is larger than the sum of its proper divisors (1247145).

3547479343 is a wasteful number, since it uses less digits than its factorization.

3547479343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247144.

The product of its digits is 3810240, while the sum is 49.

The square root of 3547479343 is about 59560.7197992099. The cubic root of 3547479343 is about 1525.1291612183.

The spelling of 3547479343 in words is "three billion, five hundred forty-seven million, four hundred seventy-nine thousand, three hundred forty-three".