355000420013 has 4 divisors (see below), whose sum is σ = 355031389920. Its totient is φ = 354969450108.

The previous prime is 355000419973. The next prime is 355000420031. The reversal of 355000420013 is 310024000553.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310024000553 = 2371 ⋅130756643.

It is a cyclic number.

It is not a de Polignac number, because 355000420013 - 2²² = 354996225709 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (355000420213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15467753 + ... + 15490686.

It is an arithmetic number, because the mean of its divisors is an integer number (88757847480).

Almost surely, 2^355000420013 is an apocalyptic number.

It is an amenable number.

355000420013 is a deficient number, since it is larger than the sum of its proper divisors (30969907).

355000420013 is a wasteful number, since it uses less digits than its factorization.

355000420013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30969906.

The product of its (nonzero) digits is 1800, while the sum is 23.

Adding to 355000420013 its reverse (310024000553), we get a palindrome (665024420566).

The spelling of 355000420013 in words is "three hundred fifty-five billion, four hundred twenty thousand, thirteen".