Base | Representation |
---|---|
bin | 1010010101010110000… |
… | …00110000100111100001 |
3 | 1020221110111022000110121 |
4 | 11022223000300213201 |
5 | 21304123420440340 |
6 | 431035523200241 |
7 | 34436425533313 |
oct | 5125300604741 |
9 | 1227414260417 |
10 | 355056421345 |
11 | 12764010356a |
12 | 5898b816081 |
13 | 27635323312 |
14 | 1328321d7b3 |
15 | 9380e0294a |
hex | 52ab0309e1 |
355056421345 has 4 divisors (see below), whose sum is σ = 426067705620. Its totient is φ = 284045137072.
The previous prime is 355056421339. The next prime is 355056421351. The reversal of 355056421345 is 543124650553.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (355056421339) and next prime (355056421351).
It can be written as a sum of positive squares in 2 ways, for example, as 38321586081 + 316734835264 = 195759^2 + 562792^2 .
It is a cyclic number.
It is not a de Polignac number, because 355056421345 - 23 = 355056421337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35505642130 + ... + 35505642139.
It is an arithmetic number, because the mean of its divisors is an integer number (106516926405).
Almost surely, 2355056421345 is an apocalyptic number.
It is an amenable number.
355056421345 is a deficient number, since it is larger than the sum of its proper divisors (71011284275).
355056421345 is an equidigital number, since it uses as much as digits as its factorization.
355056421345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71011284274.
The product of its (nonzero) digits is 1080000, while the sum is 43.
The spelling of 355056421345 in words is "three hundred fifty-five billion, fifty-six million, four hundred twenty-one thousand, three hundred forty-five".
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