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431035523200241 is a prime number
BaseRepresentation
bin110001000000001100100011…
…1001111101111010011110001
32002112011121000201112211211222
41202000121013033233103301
5422444041222414401431
64124422552530114425
7156535201041316211
oct14200310717572361
92075147021484758
10431035523200241
11115383158856773
12404156a471ba15
131566862469553b
147862332c1c241
1534c73530eb57b
hex18806473ef4f1

431035523200241 has 2 divisors, whose sum is σ = 431035523200242. Its totient is φ = 431035523200240.

The previous prime is 431035523200157. The next prime is 431035523200259. The reversal of 431035523200241 is 142002325530134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 401577712675216 + 29457810525025 = 20039404^2 + 5427505^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-431035523200241 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (431035523206241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215517761600120 + 215517761600121.

It is an arithmetic number, because the mean of its divisors is an integer number (215517761600121).

Almost surely, 2431035523200241 is an apocalyptic number.

It is an amenable number.

431035523200241 is a deficient number, since it is larger than the sum of its proper divisors (1).

431035523200241 is an equidigital number, since it uses as much as digits as its factorization.

431035523200241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 431035523200241 its reverse (142002325530134), we get a palindrome (573037848730375).

The spelling of 431035523200241 in words is "four hundred thirty-one trillion, thirty-five billion, five hundred twenty-three million, two hundred thousand, two hundred forty-one".