Base | Representation |
---|---|
bin | 110011101011001010101… |
… | …010011101010001110111 |
3 | 110120110212022002211212011 |
4 | 303223022222131101313 |
5 | 431140014014122403 |
6 | 11315154321505051 |
7 | 514361105305252 |
oct | 63531252352167 |
9 | 13513768084764 |
10 | 3551043114103 |
11 | 1149a972982a1 |
12 | 4942711a2187 |
13 | 1c9b28871974 |
14 | c3c2b1bc099 |
15 | 625865b7a6d |
hex | 33acaa9d477 |
3551043114103 has 8 divisors (see below), whose sum is σ = 3650675281472. Its totient is φ = 3451603474656.
The previous prime is 3551043114097. The next prime is 3551043114109. The reversal of 3551043114103 is 3014113401553.
It is an interprime number because it is at equal distance from previous prime (3551043114097) and next prime (3551043114109).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3551043114103 - 29 = 3551043113591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3551043114109) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48094575 + ... + 48168352.
It is an arithmetic number, because the mean of its divisors is an integer number (456334410184).
Almost surely, 23551043114103 is an apocalyptic number.
3551043114103 is a deficient number, since it is larger than the sum of its proper divisors (99632167369).
3551043114103 is an equidigital number, since it uses as much as digits as its factorization.
3551043114103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96263961.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 3551043114103 its reverse (3014113401553), we get a palindrome (6565156515656).
The spelling of 3551043114103 in words is "three trillion, five hundred fifty-one billion, forty-three million, one hundred fourteen thousand, one hundred three".
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