Base | Representation |
---|---|
bin | 1010010101011101110… |
… | …00010011100101011111 |
3 | 1020221122000101220122120 |
4 | 11022232320103211133 |
5 | 21304242024023033 |
6 | 431050202114023 |
7 | 34441144236201 |
oct | 5125670234537 |
9 | 1227560356576 |
10 | 355121314143 |
11 | 1276737a6482 |
12 | 589a94ab913 |
13 | 276458c431b |
14 | 1328bab2771 |
15 | 93869701b3 |
hex | 52aee1395f |
355121314143 has 4 divisors (see below), whose sum is σ = 473495085528. Its totient is φ = 236747542760.
The previous prime is 355121314133. The next prime is 355121314157. The reversal of 355121314143 is 341413121553.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 355121314143 - 25 = 355121314111 is a prime.
It is a super-2 number, since 2×3551213141432 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (355121314103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59186885688 + ... + 59186885693.
It is an arithmetic number, because the mean of its divisors is an integer number (118373771382).
Almost surely, 2355121314143 is an apocalyptic number.
355121314143 is a deficient number, since it is larger than the sum of its proper divisors (118373771385).
355121314143 is a wasteful number, since it uses less digits than its factorization.
355121314143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118373771384.
The product of its digits is 21600, while the sum is 33.
Adding to 355121314143 its reverse (341413121553), we get a palindrome (696534435696).
The spelling of 355121314143 in words is "three hundred fifty-five billion, one hundred twenty-one million, three hundred fourteen thousand, one hundred forty-three".
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