Base | Representation |
---|---|
bin | 10101001011110… |
… | …000010101110001 |
3 | 220202202100102120 |
4 | 111023300111301 |
5 | 1211440344441 |
6 | 55133304453 |
7 | 11543606463 |
oct | 2513602561 |
9 | 822670376 |
10 | 355403121 |
11 | 172685697 |
12 | 9b035129 |
13 | 58828608 |
14 | 352b6133 |
15 | 21304966 |
hex | 152f0571 |
355403121 has 4 divisors (see below), whose sum is σ = 473870832. Its totient is φ = 236935412.
The previous prime is 355403119. The next prime is 355403137. The reversal of 355403121 is 121304553.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 355403121 - 21 = 355403119 is a prime.
It is a super-2 number, since 2×3554031212 = 252622756833081282, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 355403091 and 355403100.
It is not an unprimeable number, because it can be changed into a prime (355403101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59233851 + ... + 59233856.
It is an arithmetic number, because the mean of its divisors is an integer number (118467708).
Almost surely, 2355403121 is an apocalyptic number.
It is an amenable number.
355403121 is a deficient number, since it is larger than the sum of its proper divisors (118467711).
355403121 is a wasteful number, since it uses less digits than its factorization.
355403121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118467710.
The product of its (nonzero) digits is 1800, while the sum is 24.
The square root of 355403121 is about 18852.1383667742. The cubic root of 355403121 is about 708.3377904710.
Adding to 355403121 its reverse (121304553), we get a palindrome (476707674).
The spelling of 355403121 in words is "three hundred fifty-five million, four hundred three thousand, one hundred twenty-one".
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