Base | Representation |
---|---|
bin | 1010010110000100111… |
… | …10010100000000011101 |
3 | 1020222110220222010211221 |
4 | 11023002132110000131 |
5 | 21310430202410240 |
6 | 431142544013341 |
7 | 34452245345446 |
oct | 5130236240035 |
9 | 1228426863757 |
10 | 355450044445 |
11 | 127822313411 |
12 | 58a7b601251 |
13 | 27698a411b2 |
14 | 132bd6042cd |
15 | 93a5756a4a |
hex | 52c279401d |
355450044445 has 4 divisors (see below), whose sum is σ = 426540053340. Its totient is φ = 284360035552.
The previous prime is 355450044413. The next prime is 355450044487. The reversal of 355450044445 is 544440054553.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 68490553849 + 286959490596 = 261707^2 + 535686^2 .
It is a cyclic number.
It is not a de Polignac number, because 355450044445 - 25 = 355450044413 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35545004440 + ... + 35545004449.
It is an arithmetic number, because the mean of its divisors is an integer number (106635013335).
Almost surely, 2355450044445 is an apocalyptic number.
It is an amenable number.
355450044445 is a deficient number, since it is larger than the sum of its proper divisors (71090008895).
355450044445 is an equidigital number, since it uses as much as digits as its factorization.
355450044445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71090008894.
The product of its (nonzero) digits is 1920000, while the sum is 43.
Adding to 355450044445 its reverse (544440054553), we get a palindrome (899890098998).
The spelling of 355450044445 in words is "three hundred fifty-five billion, four hundred fifty million, forty-four thousand, four hundred forty-five".
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