Base | Representation |
---|---|
bin | 1010010110001110101… |
… | …11011111001110000001 |
3 | 1020222200122110002202102 |
4 | 11023013113133032001 |
5 | 21311112212011231 |
6 | 431155035400145 |
7 | 34454263224341 |
oct | 5130727371601 |
9 | 1228618402672 |
10 | 355532141441 |
11 | 127864697074 |
12 | 58aa2bb3055 |
13 | 276aca56bb9 |
14 | 132ca494d21 |
15 | 93aca71acb |
hex | 52c75df381 |
355532141441 has 4 divisors (see below), whose sum is σ = 361558110000. Its totient is φ = 349506172884.
The previous prime is 355532141417. The next prime is 355532141519. The reversal of 355532141441 is 144141235553.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-355532141441 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 355532141395 and 355532141404.
It is not an unprimeable number, because it can be changed into a prime (355532141401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3012984191 + ... + 3012984308.
It is an arithmetic number, because the mean of its divisors is an integer number (90389527500).
Almost surely, 2355532141441 is an apocalyptic number.
It is an amenable number.
355532141441 is a deficient number, since it is larger than the sum of its proper divisors (6025968559).
355532141441 is an equidigital number, since it uses as much as digits as its factorization.
355532141441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6025968558.
The product of its digits is 144000, while the sum is 38.
Adding to 355532141441 its reverse (144141235553), we get a palindrome (499673376994).
The spelling of 355532141441 in words is "three hundred fifty-five billion, five hundred thirty-two million, one hundred forty-one thousand, four hundred forty-one".
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