Base | Representation |
---|---|
bin | 1010011001100010111… |
… | …01010100011101101001 |
3 | 1021011021200200002100012 |
4 | 11030301131110131221 |
5 | 21323233341231040 |
6 | 432051421221305 |
7 | 34546345233203 |
oct | 5146135243551 |
9 | 1234250602305 |
10 | 357312055145 |
11 | 128598381631 |
12 | 592bb101835 |
13 | 27904733486 |
14 | 13418a1d773 |
15 | 9463e5d865 |
hex | 5331754769 |
357312055145 has 32 divisors (see below), whose sum is σ = 454988378880. Its totient is φ = 268447928320.
The previous prime is 357312055081. The next prime is 357312055169. The reversal of 357312055145 is 541550213753.
It is not a de Polignac number, because 357312055145 - 26 = 357312055081 is a prime.
It is a super-4 number, since 4×3573120551454 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 96075596 + ... + 96079314.
It is an arithmetic number, because the mean of its divisors is an integer number (14218386840).
Almost surely, 2357312055145 is an apocalyptic number.
It is an amenable number.
357312055145 is a deficient number, since it is larger than the sum of its proper divisors (97676323735).
357312055145 is a wasteful number, since it uses less digits than its factorization.
357312055145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5905.
The product of its (nonzero) digits is 315000, while the sum is 41.
Adding to 357312055145 its reverse (541550213753), we get a palindrome (898862268898).
The spelling of 357312055145 in words is "three hundred fifty-seven billion, three hundred twelve million, fifty-five thousand, one hundred forty-five".
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