3597040133 has 4 divisors (see below), whose sum is σ = 3608532588. Its totient is φ = 3585547680.

The previous prime is 3597040121. The next prime is 3597040151. The reversal of 3597040133 is 3310407953.

3597040133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3310407953 = 337 ⋅9823169.

It can be written as a sum of positive squares in 2 ways, for example, as 68442529 + 3528597604 = 8273^2 + 59402^2 .

It is a cyclic number.

It is not a de Polignac number, because 3597040133 - 2²² = 3592845829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3597040093 and 3597040102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3597040163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5745758 + ... + 5746383.

It is an arithmetic number, because the mean of its divisors is an integer number (902133147).

Almost surely, 2^3597040133 is an apocalyptic number.

It is an amenable number.

3597040133 is a deficient number, since it is larger than the sum of its proper divisors (11492455).

3597040133 is a wasteful number, since it uses less digits than its factorization.

3597040133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11492454.

The product of its (nonzero) digits is 34020, while the sum is 35.

The square root of 3597040133 is about 59975.3293696667. The cubic root of 3597040133 is about 1532.1987173974.

The spelling of 3597040133 in words is "three billion, five hundred ninety-seven million, forty thousand, one hundred thirty-three".