3630050120533 has 4 divisors (see below), whose sum is σ = 3630053931948. Its totient is φ = 3630046309120.

The previous prime is 3630050120513. The next prime is 3630050120539. The reversal of 3630050120533 is 3350210500363.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1247972734129 + 2382077386404 = 1117127^2 + 1543398^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3630050120533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3630050120495 and 3630050120504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3630050120539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 891573 + ... + 2838133.

It is an arithmetic number, because the mean of its divisors is an integer number (907513482987).

Almost surely, 2^{3630050120533} is an apocalyptic number.

It is an amenable number.

3630050120533 is a deficient number, since it is larger than the sum of its proper divisors (3811415).

3630050120533 is a wasteful number, since it uses less digits than its factorization.

3630050120533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3811414.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 3630050120533 its reverse (3350210500363), we get a palindrome (6980260620896).

The spelling of 3630050120533 in words is "three trillion, six hundred thirty billion, fifty million, one hundred twenty thousand, five hundred thirty-three".