Base | Representation |
---|---|
bin | 1010101001110001100… |
… | …11000100000000111001 |
3 | 1021222202220212011002211 |
4 | 11110320303010000321 |
5 | 21444104413130131 |
6 | 440052152455121 |
7 | 35305305162004 |
oct | 5247063040071 |
9 | 1258686764084 |
10 | 366025130041 |
11 | 13125970977a |
12 | 5ab310aa4a1 |
13 | 28692912cac |
14 | 13a03ca653b |
15 | 97c3d605b1 |
hex | 5538cc4039 |
366025130041 has 4 divisors (see below), whose sum is σ = 366027830784. Its totient is φ = 366022429300.
The previous prime is 366025130039. The next prime is 366025130069. The reversal of 366025130041 is 140031520663.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 140031520663 = 41 ⋅3415402943.
It is a cyclic number.
It is not a de Polignac number, because 366025130041 - 21 = 366025130039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 366025129985 and 366025130012.
It is not an unprimeable number, because it can be changed into a prime (366025130941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135705 + ... + 1421926.
It is an arithmetic number, because the mean of its divisors is an integer number (91506957696).
Almost surely, 2366025130041 is an apocalyptic number.
It is an amenable number.
366025130041 is a deficient number, since it is larger than the sum of its proper divisors (2700743).
366025130041 is a wasteful number, since it uses less digits than its factorization.
366025130041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2700742.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 366025130041 in words is "three hundred sixty-six billion, twenty-five million, one hundred thirty thousand, forty-one".
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