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143111 is a prime number
BaseRepresentation
bin100010111100000111
321021022102
4202330013
514034421
63022315
71134143
oct427407
9237272
10143111
1198581
126a99b
13501a7
143a223
152c60b
hex22f07

143111 has 2 divisors, whose sum is σ = 143112. Its totient is φ = 143110.

The previous prime is 143107. The next prime is 143113. The reversal of 143111 is 111341.

143111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (111341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143111 - 22 = 143107 is a prime.

Together with 143113, it forms a pair of twin primes.

It is a Chen prime.

It is an Ulam number.

It is a junction number, because it is equal to n+sod(n) for n = 143092 and 143101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71555 + 71556.

It is an arithmetic number, because the mean of its divisors is an integer number (71556).

2143111 is an apocalyptic number.

143111 is a deficient number, since it is larger than the sum of its proper divisors (1).

143111 is an equidigital number, since it uses as much as digits as its factorization.

143111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12, while the sum is 11.

The square root of 143111 is about 378.3001453872. The cubic root of 143111 is about 52.3067422305.

Adding to 143111 its reverse (111341), we get a palindrome (254452).

It can be divided in two parts, 14 and 3111, that added together give a 5-th power (3125 = 55).

The spelling of 143111 in words is "one hundred forty-three thousand, one hundred eleven", and thus it is an iban number.