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380051055783717 = 3126683685261239
BaseRepresentation
bin101011001101001111000100…
…0001011010010111100100101
31211211122112012112021011002120
41112122132020023102330211
5344303224030240034332
63424145013355300153
7143023532311611003
oct12632361013227445
91754575175234076
10380051055783717
1110010682509663a
123676053574a659
131340a878975a36
1469bc7d8029a73
152de100068c32c
hex159a7882d2f25

380051055783717 has 4 divisors (see below), whose sum is σ = 506734741044960. Its totient is φ = 253367370522476.

The previous prime is 380051055783661. The next prime is 380051055783781. The reversal of 380051055783717 is 717387550150083.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 380051055783717 - 211 = 380051055781669 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (380051055783787) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63341842630617 + ... + 63341842630622.

It is an arithmetic number, because the mean of its divisors is an integer number (126683685261240).

Almost surely, 2380051055783717 is an apocalyptic number.

It is an amenable number.

380051055783717 is a deficient number, since it is larger than the sum of its proper divisors (126683685261243).

380051055783717 is a wasteful number, since it uses less digits than its factorization.

380051055783717 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126683685261242.

The product of its (nonzero) digits is 24696000, while the sum is 60.

The spelling of 380051055783717 in words is "three hundred eighty trillion, fifty-one billion, fifty-five million, seven hundred eighty-three thousand, seven hundred seventeen".

Divisors: 1 3 126683685261239 380051055783717