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3805112033133 = 31268370677711
BaseRepresentation
bin110111010111110010010…
…110011101111101101101
3111110202122210121012120020
4313113302112131331231
5444320332140030013
612032013324312353
7541624136423565
oct67276226357555
914422583535506
103805112033133
1112378145a8644
125155583a26b9
13217a88902a48
14d2250163da5
1568ea671c623
hex375f259df6d

3805112033133 has 4 divisors (see below), whose sum is σ = 5073482710848. Its totient is φ = 2536741355420.

The previous prime is 3805112033131. The next prime is 3805112033141. The reversal of 3805112033133 is 3313302115083.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3805112033133 - 21 = 3805112033131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3805112033094 and 3805112033103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3805112033131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 634185338853 + ... + 634185338858.

It is an arithmetic number, because the mean of its divisors is an integer number (1268370677712).

Almost surely, 23805112033133 is an apocalyptic number.

It is an amenable number.

3805112033133 is a deficient number, since it is larger than the sum of its proper divisors (1268370677715).

3805112033133 is a wasteful number, since it uses less digits than its factorization.

3805112033133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1268370677714.

The product of its (nonzero) digits is 19440, while the sum is 33.

The spelling of 3805112033133 in words is "three trillion, eight hundred five billion, one hundred twelve million, thirty-three thousand, one hundred thirty-three".

Divisors: 1 3 1268370677711 3805112033133