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381253153 = 491776483
BaseRepresentation
bin10110101110010…
…111011000100001
3222120101200000011
4112232113120201
51240100100103
6101455324521
712306412141
oct2656273041
9876350004
10381253153
11186231156
12a7820741
1360ca96a8
14388c4921
152370dd6d
hex16b97621

381253153 has 4 divisors (see below), whose sum is σ = 382030128. Its totient is φ = 380476180.

The previous prime is 381253141. The next prime is 381253163. The reversal of 381253153 is 351352183.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 381253153 - 25 = 381253121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (381253123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387751 + ... + 388732.

It is an arithmetic number, because the mean of its divisors is an integer number (95507532).

Almost surely, 2381253153 is an apocalyptic number.

It is an amenable number.

381253153 is a deficient number, since it is larger than the sum of its proper divisors (776975).

381253153 is an equidigital number, since it uses as much as digits as its factorization.

381253153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 776974.

The product of its digits is 10800, while the sum is 31.

The square root of 381253153 is about 19525.7049296562. The cubic root of 381253153 is about 725.1109797607.

It can be divided in two parts, 3812 and 53153, that added together give a palindrome (56965).

The spelling of 381253153 in words is "three hundred eighty-one million, two hundred fifty-three thousand, one hundred fifty-three".

Divisors: 1 491 776483 381253153