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1240100100103 = 71773115319597
BaseRepresentation
bin10010000010111011101…
…110011101100000000111
311101112220201010021000011
4102002323232131200013
5130304211111200403
62345405532531051
7155410556633614
oct22027356354007
94345821107004
101240100100103
11438a181a4897
1218040b020a87
138cc303174a7
144404211150b
15223d0396a6d
hex120bbb9d807

1240100100103 has 16 divisors (see below), whose sum is σ = 1260349574976. Its totient is φ = 1219930951680.

The previous prime is 1240100100101. The next prime is 1240100100181. The reversal of 1240100100103 is 3010010010421.

It is not a de Polignac number, because 1240100100103 - 21 = 1240100100101 is a prime.

It is a super-2 number, since 2×12401001001032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240100100101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63270301 + ... + 63289897.

It is an arithmetic number, because the mean of its divisors is an integer number (78771848436).

Almost surely, 21240100100103 is an apocalyptic number.

1240100100103 is a deficient number, since it is larger than the sum of its proper divisors (20249474873).

1240100100103 is a wasteful number, since it uses less digits than its factorization.

1240100100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21594.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1240100100103 its reverse (3010010010421), we get a palindrome (4250110110524).

The spelling of 1240100100103 in words is "one trillion, two hundred forty billion, one hundred million, one hundred thousand, one hundred three".

Divisors: 1 71 773 1153 19597 54883 81863 891269 1391387 15148481 22595341 63280099 1075542151 1604269211 17466198593 1240100100103