Base | Representation |
---|---|
bin | 110111011111010100001… |
… | …000010100100110000101 |
3 | 111111112112010000120012220 |
4 | 313133110020110212011 |
5 | 444433410401132403 |
6 | 12035431345202553 |
7 | 542331345136212 |
oct | 67372410244605 |
9 | 14445463016186 |
10 | 3813194942853 |
11 | 124019215431a |
12 | 517033330459 |
13 | 21877638476a |
14 | d27b9850b09 |
15 | 692cb143953 |
hex | 377d4214985 |
3813194942853 has 4 divisors (see below), whose sum is σ = 5084259923808. Its totient is φ = 2542129961900.
The previous prime is 3813194942839. The next prime is 3813194942857. The reversal of 3813194942853 is 3582494913183.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3813194942853 - 29 = 3813194942341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3813194942857) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 635532490473 + ... + 635532490478.
It is an arithmetic number, because the mean of its divisors is an integer number (1271064980952).
Almost surely, 23813194942853 is an apocalyptic number.
It is an amenable number.
3813194942853 is a deficient number, since it is larger than the sum of its proper divisors (1271064980955).
3813194942853 is a wasteful number, since it uses less digits than its factorization.
3813194942853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1271064980954.
The product of its digits is 22394880, while the sum is 60.
The spelling of 3813194942853 in words is "three trillion, eight hundred thirteen billion, one hundred ninety-four million, nine hundred forty-two thousand, eight hundred fifty-three".
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