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38421112433 = 113492828403
BaseRepresentation
bin100011110010000100…
…111010011001110001
310200011122002201221012
4203302010322121301
51112141301044213
625352253440305
72530053032024
oct436204723161
9120148081835
1038421112433
1115326797490
1275431a0095
133813c2c372
141c06a111bb
15eed0a84a8
hex8f213a671

38421112433 has 4 divisors (see below), whose sum is σ = 41913940848. Its totient is φ = 34928284020.

The previous prime is 38421112421. The next prime is 38421112451. The reversal of 38421112433 is 33421112483.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 38421112433 - 26 = 38421112369 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 38421112433.

It is not an unprimeable number, because it can be changed into a prime (38421115433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1746414191 + ... + 1746414212.

It is an arithmetic number, because the mean of its divisors is an integer number (10478485212).

Almost surely, 238421112433 is an apocalyptic number.

It is an amenable number.

38421112433 is a deficient number, since it is larger than the sum of its proper divisors (3492828415).

38421112433 is a wasteful number, since it uses less digits than its factorization.

38421112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3492828414.

The product of its digits is 13824, while the sum is 32.

The spelling of 38421112433 in words is "thirty-eight billion, four hundred twenty-one million, one hundred twelve thousand, four hundred thirty-three".

Divisors: 1 11 3492828403 38421112433