3842334613437 has 4 divisors (see below), whose sum is σ = 5123112817920. Its totient is φ = 2561556408956.

The previous prime is 3842334613409. The next prime is 3842334613441. The reversal of 3842334613437 is 7343164332483.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3842334613437 - 2⁶ = 3842334613373 is a prime.

It is a super-3 number, since 3×3842334613437³ (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3842334613437.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3842334613837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640389102237 + ... + 640389102242.

It is an arithmetic number, because the mean of its divisors is an integer number (1280778204480).

Almost surely, 2^{3842334613437} is an apocalyptic number.

It is an amenable number.

3842334613437 is a deficient number, since it is larger than the sum of its proper divisors (1280778204483).

3842334613437 is a wasteful number, since it uses less digits than its factorization.

3842334613437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1280778204482.

The product of its digits is 10450944, while the sum is 51.

The spelling of 3842334613437 in words is "three trillion, eight hundred forty-two billion, three hundred thirty-four million, six hundred thirteen thousand, four hundred thirty-seven".