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3848115404081 = 13296008877237
BaseRepresentation
bin110111111111110101100…
…011010011110100110001
3111121212122210000210110202
4313333311203103310301
51001021420020412311
612103444432004545
7545005613150114
oct67776543236461
914555583023422
103848115404081
111253a81909733
1252195a090755
1321bb4cc79c80
14d436d57457b
156a171c11e3b
hex37ff58d3d31

3848115404081 has 4 divisors (see below), whose sum is σ = 4144124281332. Its totient is φ = 3552106526832.

The previous prime is 3848115404071. The next prime is 3848115404083. The reversal of 3848115404081 is 1804045118483.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1093896351025 + 2754219053056 = 1045895^2 + 1659584^2 .

It is a cyclic number.

It is not a de Polignac number, because 3848115404081 - 26 = 3848115404017 is a prime.

It is a super-2 number, since 2×38481154040812 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3848115404083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148004438606 + ... + 148004438631.

It is an arithmetic number, because the mean of its divisors is an integer number (1036031070333).

Almost surely, 23848115404081 is an apocalyptic number.

It is an amenable number.

3848115404081 is a deficient number, since it is larger than the sum of its proper divisors (296008877251).

3848115404081 is a wasteful number, since it uses less digits than its factorization.

3848115404081 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 296008877250.

The product of its (nonzero) digits is 491520, while the sum is 47.

The spelling of 3848115404081 in words is "three trillion, eight hundred forty-eight billion, one hundred fifteen million, four hundred four thousand, eighty-one".

Divisors: 1 13 296008877237 3848115404081