3865113138703 has 16 divisors (see below), whose sum is σ = 3903467008000. Its totient is φ = 3826936303200.

The previous prime is 3865113138641. The next prime is 3865113138707. The reversal of 3865113138703 is 3078313115683.

3865113138703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3865113138703 is a prime.

It is a super-4 number, since 4×3865113138703⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3865113138707) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140112850 + ... + 140140432.

It is an arithmetic number, because the mean of its divisors is an integer number (243966688000).

Almost surely, 2^{3865113138703} is an apocalyptic number.

3865113138703 is a deficient number, since it is larger than the sum of its proper divisors (38353869297).

3865113138703 is a wasteful number, since it uses less digits than its factorization.

3865113138703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30742.

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 3865113138703 in words is "three trillion, eight hundred sixty-five billion, one hundred thirteen million, one hundred thirty-eight thousand, seven hundred three".