3911435012093 has 4 divisors (see below), whose sum is σ = 4470211442400. Its totient is φ = 3352658581788.

The previous prime is 3911435012081. The next prime is 3911435012117. The reversal of 3911435012093 is 3902105341193.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3911435012093 - 2¹⁰ = 3911435011069 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3911435012093.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3911435012593) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279388215143 + ... + 279388215156.

It is an arithmetic number, because the mean of its divisors is an integer number (1117552860600).

Almost surely, 2^{3911435012093} is an apocalyptic number.

It is an amenable number.

3911435012093 is a deficient number, since it is larger than the sum of its proper divisors (558776430307).

3911435012093 is an equidigital number, since it uses as much as digits as its factorization.

3911435012093 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 558776430306.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 3911435012093 in words is "three trillion, nine hundred eleven billion, four hundred thirty-five million, twelve thousand, ninety-three".