Base | Representation |
---|---|
bin | 111000111101100001000… |
… | …000001000101111010111 |
3 | 111212012121021020120120010 |
4 | 320331201000020233113 |
5 | 1003113033203214112 |
6 | 12154120231211303 |
7 | 552542026253334 |
oct | 70754100105727 |
9 | 14765537216503 |
10 | 3914342632407 |
11 | 127a077407589 |
12 | 532761516b33 |
13 | 2251758a173c |
14 | d76530a598b |
15 | 6bc4aed463c |
hex | 38f61008bd7 |
3914342632407 has 8 divisors (see below), whose sum is σ = 5220278968176. Its totient is φ = 2608984025792.
The previous prime is 3914342632391. The next prime is 3914342632471. The reversal of 3914342632407 is 7042362434193.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3914342632407 - 24 = 3914342632391 is a prime.
It is a super-3 number, since 3×39143426324073 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3914342632307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 144416478 + ... + 144443579.
It is an arithmetic number, because the mean of its divisors is an integer number (652534871022).
Almost surely, 23914342632407 is an apocalyptic number.
3914342632407 is a deficient number, since it is larger than the sum of its proper divisors (1305936335769).
3914342632407 is a wasteful number, since it uses less digits than its factorization.
3914342632407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288864577.
The product of its (nonzero) digits is 2612736, while the sum is 48.
The spelling of 3914342632407 in words is "three trillion, nine hundred fourteen billion, three hundred forty-two million, six hundred thirty-two thousand, four hundred seven".
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