Base | Representation |
---|---|
bin | 111000111101111101110… |
… | …000100011111100111111 |
3 | 111212020211220001220100120 |
4 | 320331331300203330333 |
5 | 1003120030210320311 |
6 | 12154240144030023 |
7 | 552560005131666 |
oct | 70757560437477 |
9 | 14766756056316 |
10 | 3914825088831 |
11 | 127a2a47811a8 |
12 | 532877002313 |
13 | 225221823507 |
14 | d769b1b1ddd |
15 | 6bc78534706 |
hex | 38f7dc23f3f |
3914825088831 has 4 divisors (see below), whose sum is σ = 5219766785112. Its totient is φ = 2609883392552.
The previous prime is 3914825088821. The next prime is 3914825088929. The reversal of 3914825088831 is 1388805284193.
3914825088831 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3914825088831 - 218 = 3914824826687 is a prime.
It is a super-2 number, since 2×39148250888312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3914825088821) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652470848136 + ... + 652470848141.
It is an arithmetic number, because the mean of its divisors is an integer number (1304941696278).
Almost surely, 23914825088831 is an apocalyptic number.
3914825088831 is a deficient number, since it is larger than the sum of its proper divisors (1304941696281).
3914825088831 is a wasteful number, since it uses less digits than its factorization.
3914825088831 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1304941696280.
The product of its (nonzero) digits is 13271040, while the sum is 60.
The spelling of 3914825088831 in words is "three trillion, nine hundred fourteen billion, eight hundred twenty-five million, eighty-eight thousand, eight hundred thirty-one".
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