Base | Representation |
---|---|
bin | 111001001011010001100… |
… | …101101010100101010001 |
3 | 111220121201212201202202102 |
4 | 321023101211222211101 |
5 | 1003333312300423213 |
6 | 12205002224530145 |
7 | 553604111344541 |
oct | 71132145524521 |
9 | 14817655652672 |
10 | 3929116420433 |
11 | 1285368873156 |
12 | 5355a5180955 |
13 | 22668b5b6749 |
14 | d8255243321 |
15 | 6c313013158 |
hex | 392d196a951 |
3929116420433 has 8 divisors (see below), whose sum is σ = 3965921658600. Its totient is φ = 3892324969728.
The previous prime is 3929116420381. The next prime is 3929116420483. The reversal of 3929116420433 is 3340246119293.
It can be written as a sum of positive squares in 4 ways, for example, as 2356617976384 + 1572498444049 = 1535128^2 + 1253993^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3929116420433 - 214 = 3929116404049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3929116420483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2873798 + ... + 4014591.
It is an arithmetic number, because the mean of its divisors is an integer number (495740207325).
Almost surely, 23929116420433 is an apocalyptic number.
It is an amenable number.
3929116420433 is a deficient number, since it is larger than the sum of its proper divisors (36805238167).
3929116420433 is a wasteful number, since it uses less digits than its factorization.
3929116420433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6893731.
The product of its (nonzero) digits is 839808, while the sum is 47.
The spelling of 3929116420433 in words is "three trillion, nine hundred twenty-nine billion, one hundred sixteen million, four hundred twenty thousand, four hundred thirty-three".
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