3931214083 has 4 divisors (see below), whose sum is σ = 3939816760. Its totient is φ = 3922611408.

The previous prime is 3931214071. The next prime is 3931214093. The reversal of 3931214083 is 3804121393.

3931214083 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3931214083 - 2⁵ = 3931214051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3931214003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4300653 + ... + 4301566.

It is an arithmetic number, because the mean of its divisors is an integer number (984954190).

Almost surely, 2^3931214083 is an apocalyptic number.

3931214083 is a deficient number, since it is larger than the sum of its proper divisors (8602677).

3931214083 is an equidigital number, since it uses as much as digits as its factorization.

3931214083 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8602676.

The product of its (nonzero) digits is 15552, while the sum is 34.

The square root of 3931214083 is about 62699.3945983532. The cubic root of 3931214083 is about 1578.2491531893.

The spelling of 3931214083 in words is "three billion, nine hundred thirty-one million, two hundred fourteen thousand, eighty-three".