Base | Representation |
---|---|
bin | 1011011110000000010… |
… | …00110100001110101101 |
3 | 1101200011002212121102000 |
4 | 11233000020310032231 |
5 | 22424021240413433 |
6 | 501010424322513 |
7 | 40320211666053 |
oct | 5570010641655 |
9 | 1350132777360 |
10 | 394065560493 |
11 | 142138810140 |
12 | 64457913439 |
13 | 2b211018487 |
14 | 15103d7c1d3 |
15 | a3b5911113 |
hex | 5bc02343ad |
394065560493 has 16 divisors (see below), whose sum is σ = 636873633600. Its totient is φ = 238827612240.
The previous prime is 394065560459. The next prime is 394065560507.
394065560493 is a `hidden beast` number, since 3 + 9 + 40 + 6 + 55 + 60 + 493 = 666.
394065560493 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 394065560493 - 212 = 394065556397 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (394065562493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 663409738 + ... + 663410331.
It is an arithmetic number, because the mean of its divisors is an integer number (39804602100).
Almost surely, 2394065560493 is an apocalyptic number.
394065560493 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
394065560493 is a deficient number, since it is larger than the sum of its proper divisors (242808073107).
394065560493 is a wasteful number, since it uses less digits than its factorization.
394065560493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1326820089 (or 1326820083 counting only the distinct ones).
The product of its (nonzero) digits is 10497600, while the sum is 54.
The spelling of 394065560493 in words is "three hundred ninety-four billion, sixty-five million, five hundred sixty thousand, four hundred ninety-three".
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