Base | Representation |
---|---|
bin | 10001111011000010101000… |
… | …01110100110011000110101 |
3 | 12011112202100100022210010222 |
4 | 20331201110032212120311 |
5 | 20131211320423141433 |
6 | 215453345451224125 |
7 | 11205265630144016 |
oct | 1075412416463065 |
9 | 164482310283128 |
10 | 39412033021493 |
11 | 11615605197740 |
12 | 4506396148045 |
13 | 18cb700894122 |
14 | 9a37a43ab00d |
15 | 4852e6493b98 |
hex | 23d8543a6635 |
39412033021493 has 16 divisors (see below), whose sum is σ = 45260979187200. Its totient is φ = 33941021053680.
The previous prime is 39412033021483. The next prime is 39412033021519.
39412033021493 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 39412033021493 - 28 = 39412033021237 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (39412033021423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3525521 + ... + 9552662.
It is an arithmetic number, because the mean of its divisors is an integer number (2828811199200).
Almost surely, 239412033021493 is an apocalyptic number.
It is an amenable number.
39412033021493 is a deficient number, since it is larger than the sum of its proper divisors (5848946165707).
39412033021493 is a wasteful number, since it uses less digits than its factorization.
39412033021493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13092632.
The product of its (nonzero) digits is 419904, while the sum is 44.
It can be divided in two parts, 3941203 and 3021493, that added together give a palindrome (6962696).
The spelling of 39412033021493 in words is "thirty-nine trillion, four hundred twelve billion, thirty-three million, twenty-one thousand, four hundred ninety-three".
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