Base | Representation |
---|---|
bin | 111001011111000011001… |
… | …100010011100101000011 |
3 | 111222122112122221120000200 |
4 | 321133003030103211003 |
5 | 1004210304012244232 |
6 | 12222433212220243 |
7 | 555255230442531 |
oct | 71370314234503 |
9 | 14878478846020 |
10 | 3950349728067 |
11 | 1293374488486 |
12 | 53973016a683 |
13 | 2286936481c2 |
14 | d92ab249151 |
15 | 6cb5719877c |
hex | 397c3313943 |
3950349728067 has 24 divisors (see below), whose sum is σ = 5715575916960. Its totient is φ = 2629175552640.
The previous prime is 3950349728053. The next prime is 3950349728107. The reversal of 3950349728067 is 7608279430593.
3950349728067 is a `hidden beast` number, since 3 + 9 + 5 + 0 + 3 + 497 + 2 + 80 + 67 = 666.
3950349728067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3950349728067 - 222 = 3950345533763 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3950349727995 and 3950349728013.
It is not an unprimeable number, because it can be changed into a prime (3950349726067) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 98323159 + ... + 98363327.
It is an arithmetic number, because the mean of its divisors is an integer number (238148996540).
Almost surely, 23950349728067 is an apocalyptic number.
3950349728067 is a deficient number, since it is larger than the sum of its proper divisors (1765226188893).
3950349728067 is a wasteful number, since it uses less digits than its factorization.
3950349728067 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58123 (or 58120 counting only the distinct ones).
The product of its (nonzero) digits is 68584320, while the sum is 63.
The spelling of 3950349728067 in words is "three trillion, nine hundred fifty billion, three hundred forty-nine million, seven hundred twenty-eight thousand, sixty-seven".
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