Base | Representation |
---|---|
bin | 111001101000000101111… |
… | …000010101011001010101 |
3 | 112000120121021201022022000 |
4 | 321220011320111121111 |
5 | 1004340144434010233 |
6 | 12231120433025513 |
7 | 556050640603221 |
oct | 71500570253125 |
9 | 15016537638260 |
10 | 3960058500693 |
11 | 12974a6870009 |
12 | 53b59b6b5299 |
13 | 22957cbb9889 |
14 | d994c83d781 |
15 | 6d0246cbd13 |
hex | 39a05e15655 |
3960058500693 has 16 divisors (see below), whose sum is σ = 6056003443200. Its totient is φ = 2554876451520.
The previous prime is 3960058500649. The next prime is 3960058500721.
3960058500693 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3960058500693 - 213 = 3960058492501 is a prime.
It is a hoax number, since the sum of its digits (54) coincides with the sum of the digits of its distinct prime factors.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3960058500493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2365625508 + ... + 2365627181.
It is an arithmetic number, because the mean of its divisors is an integer number (378500215200).
Almost surely, 23960058500693 is an apocalyptic number.
It is an amenable number.
3960058500693 is a deficient number, since it is larger than the sum of its proper divisors (2095944942507).
3960058500693 is a wasteful number, since it uses less digits than its factorization.
3960058500693 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4731252729 (or 4731252723 counting only the distinct ones).
The product of its (nonzero) digits is 5248800, while the sum is 54.
The spelling of 3960058500693 in words is "three trillion, nine hundred sixty billion, fifty-eight million, five hundred thousand, six hundred ninety-three".
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