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39742353471121 = 75677479067303
BaseRepresentation
bin10010000100101001111001…
…10111000111011010010001
312012201022221221112020111221
421002110330313013122101
520202114314442033441
6220305215105005041
711241201365505610
oct1102247467073221
9165638857466457
1039742353471121
11117327014a9574
12455a401923781
1319238c3295892
149b577c331877
1548dbca9798d1
hex24253cdc7691

39742353471121 has 4 divisors (see below), whose sum is σ = 45419832538432. Its totient is φ = 34064874403812.

The previous prime is 39742353471113. The next prime is 39742353471209. The reversal of 39742353471121 is 12117435324793.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 39742353471121 - 23 = 39742353471113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (39742353471721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2838739533645 + ... + 2838739533658.

It is an arithmetic number, because the mean of its divisors is an integer number (11354958134608).

Almost surely, 239742353471121 is an apocalyptic number.

It is an amenable number.

39742353471121 is a deficient number, since it is larger than the sum of its proper divisors (5677479067311).

39742353471121 is an equidigital number, since it uses as much as digits as its factorization.

39742353471121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5677479067310.

The product of its digits is 3810240, while the sum is 52.

The spelling of 39742353471121 in words is "thirty-nine trillion, seven hundred forty-two billion, three hundred fifty-three million, four hundred seventy-one thousand, one hundred twenty-one".

Divisors: 1 7 5677479067303 39742353471121