Base | Representation |
---|---|
bin | 1011000001010100111101… |
… | …1011011001100101111001 |
3 | 1120220102012220100201022021 |
4 | 2300111033123121211321 |
5 | 3042013001420343133 |
6 | 41434401204354441 |
7 | 2360312225550511 |
oct | 260251733314571 |
9 | 46812186321267 |
10 | 12117435324793 |
11 | 3951a80381537 |
12 | 14385346a5a21 |
13 | 69b891451856 |
14 | 2dc6b647a841 |
15 | 160307b7252d |
hex | b054f6d9979 |
12117435324793 has 2 divisors, whose sum is σ = 12117435324794. Its totient is φ = 12117435324792.
The previous prime is 12117435324769. The next prime is 12117435324811. The reversal of 12117435324793 is 39742353471121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12002088146409 + 115347178384 = 3464403^2 + 339628^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12117435324793 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12117435324793.
It is not a weakly prime, because it can be changed into another prime (12117435324193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6058717662396 + 6058717662397.
It is an arithmetic number, because the mean of its divisors is an integer number (6058717662397).
Almost surely, 212117435324793 is an apocalyptic number.
It is an amenable number.
12117435324793 is a deficient number, since it is larger than the sum of its proper divisors (1).
12117435324793 is an equidigital number, since it uses as much as digits as its factorization.
12117435324793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3810240, while the sum is 52.
The spelling of 12117435324793 in words is "twelve trillion, one hundred seventeen billion, four hundred thirty-five million, three hundred twenty-four thousand, seven hundred ninety-three".
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