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3983128166701 = 35951110793251
BaseRepresentation
bin111001111101100100111…
…100001000000100101101
3112002210011001100202200101
4321331210330020010231
51010224421302313301
612245453540031101
7560525425535545
oct71754474100455
915083131322611
103983128166701
1112a6265012592
12543b59692491
1322b7b852b518
14daada6a4325
156d924b9d701
hex39f64f0812d

3983128166701 has 4 divisors (see below), whose sum is σ = 3983238995904. Its totient is φ = 3983017337500.

The previous prime is 3983128166669. The next prime is 3983128166767. The reversal of 3983128166701 is 1076618213893.

3983128166701 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3983128166701 - 25 = 3983128166669 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3983128166791) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55360675 + ... + 55432576.

It is an arithmetic number, because the mean of its divisors is an integer number (995809748976).

Almost surely, 23983128166701 is an apocalyptic number.

It is an amenable number.

3983128166701 is a deficient number, since it is larger than the sum of its proper divisors (110829203).

3983128166701 is a wasteful number, since it uses less digits than its factorization.

3983128166701 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110829202.

The product of its (nonzero) digits is 2612736, while the sum is 55.

The spelling of 3983128166701 in words is "three trillion, nine hundred eighty-three billion, one hundred twenty-eight million, one hundred sixty-six thousand, seven hundred one".

Divisors: 1 35951 110793251 3983128166701