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3991523122013 = 7570217588859
BaseRepresentation
bin111010000101011001010…
…100010101101101011101
3112010120211002221200102012
4322011121110111231131
51010344114404401023
612253402545041005
7561243443510120
oct72053124255535
915116732850365
103991523122013
1112a988281a789
12545701026165
1322c5258379bb
14db2955bc3b7
156dc66bb2978
hex3a159515b5d

3991523122013 has 4 divisors (see below), whose sum is σ = 4561740710880. Its totient is φ = 3421305533148.

The previous prime is 3991523122009. The next prime is 3991523122051. The reversal of 3991523122013 is 3102213251993.

3991523122013 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3991523122013 - 22 = 3991523122009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3991523124013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285108794423 + ... + 285108794436.

It is an arithmetic number, because the mean of its divisors is an integer number (1140435177720).

Almost surely, 23991523122013 is an apocalyptic number.

It is an amenable number.

3991523122013 is a deficient number, since it is larger than the sum of its proper divisors (570217588867).

3991523122013 is an equidigital number, since it uses as much as digits as its factorization.

3991523122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 570217588866.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 3991523122013 in words is "three trillion, nine hundred ninety-one billion, five hundred twenty-three million, one hundred twenty-two thousand, thirteen".

Divisors: 1 7 570217588859 3991523122013