Base | Representation |
---|---|
bin | 100101001111101101… |
… | …110101001101000011 |
3 | 10211020010020012100111 |
4 | 211033231311031003 |
5 | 1123400440321011 |
6 | 30212213532151 |
7 | 2614020261265 |
oct | 451755651503 |
9 | 124203205314 |
10 | 39992120131 |
11 | 15a62566857 |
12 | 7901344057 |
13 | 3a04553a12 |
14 | 1d15519b35 |
15 | 1090e7c121 |
hex | 94fb75343 |
39992120131 has 4 divisors (see below), whose sum is σ = 40843016352. Its totient is φ = 39141223912.
The previous prime is 39992120089. The next prime is 39992120141. The reversal of 39992120131 is 13102129993.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 39992120131 - 215 = 39992087363 is a prime.
It is a super-2 number, since 2×399921201312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (39992120141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425448040 + ... + 425448133.
It is an arithmetic number, because the mean of its divisors is an integer number (10210754088).
Almost surely, 239992120131 is an apocalyptic number.
39992120131 is a deficient number, since it is larger than the sum of its proper divisors (850896221).
39992120131 is an equidigital number, since it uses as much as digits as its factorization.
39992120131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850896220.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 39992120131 in words is "thirty-nine billion, nine hundred ninety-two million, one hundred twenty thousand, one hundred thirty-one".
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