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399960000001 = 1313053129771
BaseRepresentation
bin1011101000111110111…
…10010100011000000001
31102020100220022011022101
411310133132110120001
523023104230000001
6503423350510401
740616244622642
oct5643736243001
91366326264271
10399960000001
11144692aa1851
1265621965401
132b9402747c3
1415502b4d6c9
15a60d146a01
hex5d1f794601

399960000001 has 4 divisors (see below), whose sum is σ = 403013129904. Its totient is φ = 396906870100.

The previous prime is 399959999987. The next prime is 399960000019. The reversal of 399960000001 is 100000069993.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 399960000001 - 233 = 391370065409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (399960000071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1526564755 + ... + 1526565016.

It is an arithmetic number, because the mean of its divisors is an integer number (100753282476).

Almost surely, 2399960000001 is an apocalyptic number.

It is an amenable number.

399960000001 is a deficient number, since it is larger than the sum of its proper divisors (3053129903).

399960000001 is a wasteful number, since it uses less digits than its factorization.

399960000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3053129902.

The product of its (nonzero) digits is 13122, while the sum is 37.

Adding to 399960000001 its reverse (100000069993), we get a palindrome (499960069994).

The spelling of 399960000001 in words is "three hundred ninety-nine billion, nine hundred sixty million, one", and thus it is an aban number.

Divisors: 1 131 3053129771 399960000001