4000000013 has 4 divisors (see below), whose sum is σ = 4007030460. Its totient is φ = 3992969568.

The previous prime is 4000000009. The next prime is 4000000019. The reversal of 4000000013 is 3100000004.

4000000013 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2572822729 + 1427177284 = 50723^2 + 37778^2 .

It is a cyclic number.

It is not a de Polignac number, because 4000000013 - 2² = 4000000009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4000000019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3514370 + ... + 3515507.

It is an arithmetic number, because the mean of its divisors is an integer number (1001757615).

Almost surely, 2^4000000013 is an apocalyptic number.

It is an amenable number.

4000000013 is a deficient number, since it is larger than the sum of its proper divisors (7030447).

4000000013 is an equidigital number, since it uses as much as digits as its factorization.

4000000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7030446.

The product of its (nonzero) digits is 12, while the sum is 8.

The square root of 4000000013 is about 63245.5533061416. The cubic root of 4000000013 is about 1587.4010536879.

Adding to 4000000013 its reverse (3100000004), we get a palindrome (7100000017).

Subtracting from 4000000013 its reverse (3100000004), we obtain a palindrome (900000009).

It can be divided in two parts, 400000001 and 3, that added together give a palindrome (400000004).

The spelling of 4000000013 in words is "four billion, thirteen", and thus it is an aban number.