4000345133 has 4 divisors (see below), whose sum is σ = 4000542108. Its totient is φ = 4000148160.

The previous prime is 4000345117. The next prime is 4000345171. The reversal of 4000345133 is 3315430004.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2920105444 + 1080239689 = 54038^2 + 32867^2 .

It is a cyclic number.

It is not a de Polignac number, because 4000345133 - 2⁴ = 4000345117 is a prime.

It is a super-2 number, since 2×4000345133² = 32005522366233575378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4000345099 and 4000345108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4000345103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63998 + ... + 109983.

It is an arithmetic number, because the mean of its divisors is an integer number (1000135527).

Almost surely, 2^4000345133 is an apocalyptic number.

It is an amenable number.

4000345133 is a deficient number, since it is larger than the sum of its proper divisors (196975).

4000345133 is a wasteful number, since it uses less digits than its factorization.

4000345133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 196974.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 4000345133 is about 63248.2816604530. The cubic root of 4000345133 is about 1587.4467060291.

Adding to 4000345133 its reverse (3315430004), we get a palindrome (7315775137).

The spelling of 4000345133 in words is "four billion, three hundred forty-five thousand, one hundred thirty-three".