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40005014053 = 211189597223
BaseRepresentation
bin100101010000011111…
…000001001000100101
310211021000111021111011
4211100133001020211
51123412240422203
630213354142221
72614235003014
oct452037011045
9124230437434
1040005014053
1115a69873194
127905721971
133a07119864
141d17114a7b
15109217776d
hex9507c1225

40005014053 has 4 divisors (see below), whose sum is σ = 40194611488. Its totient is φ = 39815416620.

The previous prime is 40005014003. The next prime is 40005014087. The reversal of 40005014053 is 35041050004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40005014053 - 225 = 39971459621 is a prime.

It is a super-2 number, since 2×400050140532 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40005014003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94798401 + ... + 94798822.

It is an arithmetic number, because the mean of its divisors is an integer number (10048652872).

Almost surely, 240005014053 is an apocalyptic number.

It is an amenable number.

40005014053 is a deficient number, since it is larger than the sum of its proper divisors (189597435).

40005014053 is a wasteful number, since it uses less digits than its factorization.

40005014053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189597434.

The product of its (nonzero) digits is 1200, while the sum is 22.

Adding to 40005014053 its reverse (35041050004), we get a palindrome (75046064057).

The spelling of 40005014053 in words is "forty billion, five million, fourteen thousand, fifty-three".

Divisors: 1 211 189597223 40005014053