Base | Representation |
---|---|
bin | 10010001100100000010110… |
… | …01001010100111110100011 |
3 | 12020200010020012120202222120 |
4 | 21012100023021110332203 |
5 | 20221024241143333011 |
6 | 221033150035035323 |
7 | 11266531124102400 |
oct | 1106201311247643 |
9 | 166603205522876 |
10 | 40012102324131 |
11 | 11827045715343 |
12 | 45a274413bb43 |
13 | 19431819a78c2 |
14 | 9c484b9312a7 |
15 | 495c17450a06 |
hex | 24640b254fa3 |
40012102324131 has 12 divisors (see below), whose sum is σ = 62059587278472. Its totient is φ = 22864058470848.
The previous prime is 40012102324081. The next prime is 40012102324199. The reversal of 40012102324131 is 13142320121004.
It is not a de Polignac number, because 40012102324131 - 211 = 40012102322083 is a prime.
It is a super-2 number, since 2×400121023241312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (40012101324131) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 136095585990 + ... + 136095586283.
It is an arithmetic number, because the mean of its divisors is an integer number (5171632273206).
Almost surely, 240012102324131 is an apocalyptic number.
40012102324131 is a deficient number, since it is larger than the sum of its proper divisors (22047484954341).
40012102324131 is a wasteful number, since it uses less digits than its factorization.
40012102324131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 272191172290 (or 272191172283 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 40012102324131 its reverse (13142320121004), we get a palindrome (53154422445135).
The spelling of 40012102324131 in words is "forty trillion, twelve billion, one hundred two million, three hundred twenty-four thousand, one hundred thirty-one".
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