Base | Representation |
---|---|
bin | 101101011111010110100001… |
… | …0010110100101000010110011 |
3 | 1221110202100121022010200212112 |
4 | 1122332231002112211002303 |
5 | 404421240143230144103 |
6 | 3535002344311515535 |
7 | 150165444335154053 |
oct | 13276550226450263 |
9 | 1843670538120775 |
10 | 400133151412403 |
11 | 106549575582592 |
12 | 38a6459a988bab |
13 | 142365182ab846 |
14 | 70b4795491563 |
15 | 313d5ac993cd8 |
hex | 16beb425a50b3 |
400133151412403 has 4 divisors (see below), whose sum is σ = 405198128012640. Its totient is φ = 395068174812168.
The previous prime is 400133151412289. The next prime is 400133151412451. The reversal of 400133151412403 is 304214151331004.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 400133151412403 - 212 = 400133151408307 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 400133151412403.
It is not an unprimeable number, because it can be changed into a prime (400133151412103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2532488300000 + ... + 2532488300157.
It is an arithmetic number, because the mean of its divisors is an integer number (101299532003160).
Almost surely, 2400133151412403 is an apocalyptic number.
400133151412403 is a deficient number, since it is larger than the sum of its proper divisors (5064976600237).
400133151412403 is an equidigital number, since it uses as much as digits as its factorization.
400133151412403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5064976600236.
The product of its (nonzero) digits is 17280, while the sum is 32.
The spelling of 400133151412403 in words is "four hundred trillion, one hundred thirty-three billion, one hundred fifty-one million, four hundred twelve thousand, four hundred three".
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